A man
rewards his three children based on their yearly academic performance. If the
first child gets twice
as much as the third, and the second gets half
as much as the third, Calculate how much money each gets assuming total amount
of ¥875000 is the reward
Solution
Let the
children be A, B
& C
From the question,
we deduce that
A = 2C
and
B = ½C
Let B’s
share = ¥x
Then if B is
half of C,
I.e. B
= ½ C and b =
¥x
Then x
= ½C
By cross
multiplication, we have
C = 2 * x
C = 2x
If A
= 2C, and C =
2x
Then A
= 2 * 2x
A = 4x
Thus ratio A
: B : C = 4x : x : 2x
Total ratio
= 4x + 1x + 2x = 7x
Total amount
shared = ¥875000
A’s share = 4x/7x
* 875000
= ¥500,000
B’s share = 1x/7x
* 875000
= ¥125,000
C’s share = 2x/7x
* 875000
= ¥250,000
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