Ratio: Ratio that leads to Linear equation

A sum of money worth N103,025 consists of equal number of N1,000 notes, N500 notes, N50 notes, N20 notes, N10 notes and N5 notes respectively. Calculate how much of each note is contained in the sum.
Solution 
Given that
Total amount = N103,025
Currency notes = 1000, 500, 50, 20, 10 and 5
Number of notes involved = ?
Let no of notes = n
Then (1000*n) + (500*n) + (50*n) + (20*n) + (10*n) + (5*n) =  N103,025
1000n + 500n + 50n + 20n + 10n + 5n = N103,025
This forms an equation in n. simplifying further, we get
1585n = 103025
The coefficient of n is 1585
Divide both side by 1585 (coefficient of n) 
n = 103025 ÷ 1585     
n = 65
Thus, number of currency notes = 65 pieces in each denomination
Amount of each note is computed as follows
N1,000 notes = N1000 * 65
= N65,000
N500 notes   = N500 * 65
= N32,500
N50 notes   = N50 * 65
= N3,250
N20 notes   = N20 * 65
= N1,300
N10 notes   = N10 * 65
              = N650
N5 notes   = N5 * 65
             = N325
Check for correctness
To confirm, we sum up the values of all the denominations as follows

Denomination
Number
Amount
N1000
65
65,000.00
N500
65
32,500.00
N50
65
3,250.00
N20
65
1,300.00
N10
65
650.00
N5
65
325.00
103,025.00

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